C Programming break and continue Statement
The break statement terminates the loop, whereas continue statement forces the next iteration of the loop. In this tutorial, you will learn to use break and continue with the help of examples.
It is sometimes desirable to skip some statements inside the loop or terminate the loop immediately without checking the test expression.
In such cases,
break
and continue
statements are used.break Statement
The break statement terminates the loop (for, while and do...while loop) immediately when it is encountered. Its syntax is:
break;
The break statement is almost always used with if...else statement inside the loop.
How break statement works?

Example 1: break statement
// Program to calculate the sum of maximum of 10 numbers
// If negative number is entered, loop terminates and sum is displayed
# include <stdio.h>
int main()
{
int i;
double number, sum = 0.0;
for(i=1; i <= 10; ++i)
{
printf("Enter a n%d: ",i);
scanf("%lf",&number);
// If user enters negative number, loop is terminated
if(number < 0.0)
{
break;
}
sum += number; // sum = sum + number;
}
printf("Sum = %.2lf",sum);
return 0;
}
Output
Enter a n1: 2.4 Enter a n2: 4.5 Enter a n3: 3.4 Enter a n4: -3 Sum = 10.30
This program calculates the sum of maximum of 10 numbers. Why maximum of 10 numbers? It's because if the user enters negative number, the break statement is executed which terminates the
for
loop, and sum is displayed.
In C,
break
is also used with switch statement.continue Statement
The continue statement skips statements after it inside the loop. Its syntax is:
continue;
The continue statement is almost always used with
if...else
statement.How continue statement works?

Example 2: continue statement
// Program to calculate sum of maximum of 10 numbers
// Negative numbers are skipped from calculation
# include <stdio.h>
int main()
{
int i;
double number, sum = 0.0;
for(i=1; i <= 10; ++i)
{
printf("Enter a n%d: ",i);
scanf("%lf",&number);
if(number < 0.0)
{
continue;
}
sum += number; // sum = sum + number;
}
printf("Sum = %.2lf",sum);
return 0;
}
Output
Enter a n1: 1.1 Enter a n2: 2.2 Enter a n3: 5.5 Enter a n4: 4.4 Enter a n5: -3.4 Enter a n6: -45.5 Enter a n7: 34.5 Enter a n8: -4.2 Enter a n9: -1000 Enter a n10: 12 Sum = 59.70
In the program, when the user enters positive number, the sum is calculated using
sum += number;
statement.
When the user enters negative number, the
continue
statement is executed and skips the negative number from calculation
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